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Raj Dewan
Asked: 2022-11-11T05:35:40+05:30 In:

A long taut string is connected to a harmonic oscillator of frequency `f` at one end. The oscillator oscillates with an amplitude `a_(0)` and delivers power `P_(0)` to the string. Due to dissipation of energy the amplitude of wave goes on decreasing with distance `x` from the oscillator given as `a = a_(0)e^( –kx)`. In what length of the string `(3/4)th` of the energy supplied by the oscillator gets dissipated?

A long taut string is connected to a harmonic oscillator of frequency `f` at one end. The oscillator oscillates with an amplitude `a_(0)` and delivers power `P_(0)` to the string. Due to dissipation of energy the amplitude of wave goes on decreasing with distance `x` from the oscillator given as `a = a_(0)e^( –kx)`. In what length of the string `(3/4)th` of the energy supplied by the oscillator gets dissipated?
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1 Answer

  1. Correct Answer – `(ln 2)/(k)`

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