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Narmada Sharad Subramaniam
Asked: 2022-11-09T21:55:22+05:30 In:

A light ray is incident on a horizontal plane mirror at an angle of `45^(@)`. At what angle should a second plane mirror be placed in order that the refelcted ray finally be reflected horizontally form the second mirror, as shown in figure
image
A. `theta=30^(@)`
B. `theta=24^(@)`
C. `theta=22.5^(@)`
D. `theta=67.5^(@)`

A light ray is incident on a horizontal plane mirror at an angle of `45^(@)`. At what angle should a second plane mirror be placed in order that the refelcted ray finally be reflected horizontally form the second mirror, as shown in figure
image
A. `theta=30^(@)`
B. `theta=24^(@)`
C. `theta=22.5^(@)`
D. `theta=67.5^(@)`
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1 Answer

  1. (c) From figure `CD=` emergent ray and `CD` is parallel to `PQ` and `BC` is a line intersecting these parallel lines,
    So, `/_DCB/_CBQ=180^(@)`
    `/_DCN+/_NCB+/_CBQ=180^(@)`
    `alpha+alpha+45^(@)=180^(@)`
    `alpha=67.5^(@)`
    But `/_NCS=90^(@)`
    So, second mirror is at an angle of `22.5^(@)` with horizontal .

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