A gas expands from a volume of 1`m^(3)` to a volume of`2m^(3)` against an external pressure of`10^(5) Nm^(-2)`. The work done by the gas will be
A. `10^(5) kJ `
B. ` 10^(2) kJ`
C. ` 10^(2) J`
D. `10^(3)J`
A. `10^(5) kJ `
B. ` 10^(2) kJ`
C. ` 10^(2) J`
D. `10^(3)J`
Correct Answer – b
`w = – PDeltaV = – 10^(5) Nm^(-2) ( 2-1) m^(3) = – 10^(5) Nm = – 10^(5) J = -10^(2) kJ `