A fair coin is tossed for 10 times, what is the probability of getting 2 heads
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Probability of getting head in tossing a coin is p =1/2 and probability of not getting a head is also q=1/2 in one trial.
The probablprob distribution is binomial. So probability of getting r heads in n trial is
P(x = r) = nCr×p^r×q(^(n-r)
So probability of getting 2 heads in 10 trial is
P (x=2) = 10C2×(1/2)^2(1/2)^10
=45/2^10 =45/1024