A disc of mass 2 kg and diameter 40 cm is free to rotate about an axis passing through its centre and perpendicular to its plane. If a force of 50 N is applied to the disc tangentially Its angular acceleration will be
A. `100 rad//s^(2)`
B. `25 rad//s^(2)`
C. `250 rad//s^(2)`
D. `500 rad//s^(2)`
A. `100 rad//s^(2)`
B. `25 rad//s^(2)`
C. `250 rad//s^(2)`
D. `500 rad//s^(2)`
Correct Answer – C
`tau = I alpha`
`therefore alpha =(tau)/(I)=(rF)/(I)=(0.2xx50)/(mR^(2)/2)=(10xx2)/(2xx0.2xx0.2)`
`= 250 rad//s^(2)`