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Urmila Sundaram
Asked: 2022-11-01T17:06:42+05:30 In:

A disc having radius `R` is rolling without slipping on a horizontal (`x-z`) plane. Centre of the disc has a velocity `v` and acceleration `a` as shown. image
Speed of point `P` having coordinates `(x,y)` is
A. `(vsqrt(x^(2)+y^(2)))/(R`
B. `(vsqrt(x^(2)+(y+R)^(2)))/R`
C. `(vsqrt(v^(2)+(y-R)^(2)))/R`
D. none of these

A disc having radius `R` is rolling without slipping on a horizontal (`x-z`) plane. Centre of the disc has a velocity `v` and acceleration `a` as shown. image
Speed of point `P` having coordinates `(x,y)` is
A. `(vsqrt(x^(2)+y^(2)))/(R`
B. `(vsqrt(x^(2)+(y+R)^(2)))/R`
C. `(vsqrt(v^(2)+(y-R)^(2)))/R`
D. none of these
Parabola
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1 Answer

  1. Correct Answer – B
    `omega=v/R`, Distance of `P` from origin
    `r=sqrt(x^(2)+y^(2))`
    origin is instantaneous centre of rotatio. So,
    `v_(P)=omegar=(vsqrt(x^(2)+y^(2)))/R`

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