A dice is rolled twice. Find the probability that 3 will come exactly one time.
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When a dice is rolled twice, the total outcomes = 62 = 36possible outcomes that 3\xa0will come one time is (1, 3), (2, 3) (3, 3) (4, 3) (5,3) (3, 1) (3, 2) (3, 4) (3, 5) (3, 6) = 10P(3\xa0will come up exactly one time) =\xa0{tex}\\frac { 10 } { 36 } = \\frac { 5 } { 18 }{/tex}