Correct Answer – Option 3 : 3/8

GIVEN :

A dice is rolled and at the same time 2 coins are tossed.

CONCEPT :

Probability.

FORMULA USED :

\(\rm P(H) = \dfrac{Number \ of \ Favourable \ Outcomes}{Total \ Number \ of \ Outcomes}\)

CALCULATION :

Probability of getting a number more than 3

⇒ Number of ways a number more than 3 can come = {4 , 5 , 6} = 3

Total number of possible outcome = {1,2,3,4,5,6} = 6

∴ P(A) = (Number of ways A can occur)/(Total number of possible outcomes)

⇒ Probability = 3/6 = 1/2

Probability of getting atleast one head

⇒ Number of ways atleast one head can occur = {(H,T) (T,H) (H,H)} = 3

Total number of possible outcomes = {(H,T) (T,H) (H,H) (T,T)} = 4

∴ Probability = 3/4

∴ The probability of getting a number more than 3 and atleast one head

⇒ (1/2) × (3/4) = 3/8

∴ The probability of getting a number more than 3 and atleast one head is 3/8