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Biren Ram Ramroop
Asked: 2022-11-06T08:09:02+05:30 In:

A conical pendulum consists of a mass `M` suspended from a string of length `l`. The mass executes a circle of radius `R` in a horizontal plane with speed `v`. At time `t`, the mass is at position `Rhat i` and has velocity `v hat j`. At time `t`, the angular momentum vector of the mass `M` about the point from which the string suspended is
image
A. `M upsilonRhatk`
B. `m upsilonlhatk`
C. `M upsilonl[(sqrt(l^(2)-R^(2))/lhati)+R/lhatk]`
D. `-M upsilonl[(sqrt(l^(2)-R^(2))/lhati)+R/lhatk]`

A conical pendulum consists of a mass `M` suspended from a string of length `l`. The mass executes a circle of radius `R` in a horizontal plane with speed `v`. At time `t`, the mass is at position `Rhat i` and has velocity `v hat j`. At time `t`, the angular momentum vector of the mass `M` about the point from which the string suspended is
image
A. `M upsilonRhatk`
B. `m upsilonlhatk`
C. `M upsilonl[(sqrt(l^(2)-R^(2))/lhati)+R/lhatk]`
D. `-M upsilonl[(sqrt(l^(2)-R^(2))/lhati)+R/lhatk]`
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  1. Correct Answer – C
    `vec(r)=Rhati-sqrt(l^(2)-R^(2)hatk)`
    `vec(P)=Mupsilonhatj`
    `vec(L)=vec(r)xxvec(P)`

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Radheshyam Kapur
Asked: 2022-11-04T23:39:24+05:30 In:

A conical pendulum consists of a mass `M` suspended from a strong sling of length `l`. The mass executes a circle of radius `R` in a horizontal plane with speed `v`. At time `t`, the mass is at position `Rhati` and `vhatj` velocity. At time `t` the angular momentum vector of mass `M` about the point from which the string passes on the ceiling is
image
A. `MvRhatk`
B. `Mvlhatk`
C. `Mvl[sqrt((l^2-R^2)/l)hati+R/lhatk]`
D. `-Mvl[sqrt((l^(2)-R^(2))/l)hati+R/lhatk]`

A conical pendulum consists of a mass `M` suspended from a strong sling of length `l`. The mass executes a circle of radius `R` in a horizontal plane with speed `v`. At time `t`, the mass is at position `Rhati` and `vhatj` velocity. At time `t` the angular momentum vector of mass `M` about the point from which the string passes on the ceiling is
image
A. `MvRhatk`
B. `Mvlhatk`
C. `Mvl[sqrt((l^2-R^2)/l)hati+R/lhatk]`
D. `-Mvl[sqrt((l^(2)-R^(2))/l)hati+R/lhatk]`
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1 Answer

  1. Correct Answer – C
    From the figure in questions position vector if mass `vecr=Rhati-sqrt(l^(2)+R^(3)hatk)`
    Linear moment `vecp=Mvhatj`
    `vecL=vecvxxvecp`
    substituting the values, we get result

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