A chord of the parabola y = x2 – 2 + 5 = joins the point with the abscissas x1 x 1 , x2 = 3 Then the equation of the tangent to the parabola parallel to the chord is :
(A) 2x – y + 5/4 = 0
(B) 2x – y + 2 = 0
(C) 2x – y + 1 = 0
(D) 2x + y + 1 = 0
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A chord of the parabola y = x2 – 2 + 5 = joins the point with the abscissas x1 x 1 , x2 = 3 Then the equation of the tangent to the parabola parallel to the chord is :
(A) 2x – y + 5/4 = 0
(B) 2x – y + 2 = 0
(C) 2x – y + 1 = 0
(D) 2x + y + 1 = 0
A chord of the parabola y = x2 – 2 + 5 = joins the point with the abscissas x1 x 1 , x2 = 3 Then the equation of the tangent to the parabola parallel to the chord is :
(A) 2x – y + 5/4 = 0
(B) 2x – y + 2 = 0
(C) 2x – y + 1 = 0
(D) 2x + y + 1 = 0
Correct option (C ) 2x – y + 1 = 0
Explanation:
Equation of chord joining the points Equation of chord joining the points P(1,4) & (3,8) on the parabola is 2x – y + 2 = 0
Tangent parallel to this chord will have the slope i.e dy/dx = 2
∴ Equation of tangent at (α ,β) on the curve with slope 2 is 2x – y + 1 = 0