A business man of 70 kg weight requires 2800 kcal energy daily. How many glucose molecules and ATP molecules does he require to produce this much energy ?
A. 20 molecules of glucose and 384 molecules of ATP
B. 11 molecules of glucose and 380 molecules of ATP
C. 1 Molecule of glucose and 38 molecules of ATP
D. 6 molecules of glucose and 584 molecules of ATP
A. 20 molecules of glucose and 384 molecules of ATP
B. 11 molecules of glucose and 380 molecules of ATP
C. 1 Molecule of glucose and 38 molecules of ATP
D. 6 molecules of glucose and 584 molecules of ATP
Correct Answer – B
One molecule of glucose yields 686 Kcal of which only 262. 8 Kcal(= 36 ATP) is usable and rest is lost as heat.
1 ATP yields 7.3 Kcal and accordingly (1) number of glucose for 2800 Kcal energy will be`2800/262.8=11`(ii) number of ATP will be `2800/7.3=384`.