A bulb rated as100W-220V IS CONNECTED ACROSS 110V SUPPLY THEN POWER DEVELOPED BY IT?
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P= 100 W , V = 220 V .Therefore R = (V^2÷P)= 484 OhmIf V= 110 VTherefore P = (V^2÷R) = [(110×110)÷484] W = 25W.☺☺☺☺☺☺