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Munni Mukund Kulkarni
Asked: 2022-11-07T11:31:23+05:30 In:

A brass disc has a hole of diameter 2.5 cm at `27^(@)C`. Find the change in the diameter of the hole of the disc when heated to `327^(@)C`. Given coefficient of linear expansion of brass = ` 1.9 xx 10^(-5) .^(@)C^(-1)`

A brass disc has a hole of diameter 2.5 cm at `27^(@)C`. Find the change in the diameter of the hole of the disc when heated to `327^(@)C`. Given coefficient of linear expansion of brass = ` 1.9 xx 10^(-5) .^(@)C^(-1)`
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  1. Here, `D_(27) = 2.5 cm` ,
    `Delta T = 327 – 27 = 300^(@)C`
    `alpha = 1.9 xx 10^(-5) .^(@)C^(-1) , D_(327)-D_(27) = ?`
    `D_(327) = D_(27)[1+alpha Delta T] D_(27) + D_(27) alpha Delta T`
    Change in diameter = `D_(327)-D_(27) = D_(27) alpha Delta T`
    `=2.5 xx 91.9 xx 10^(-5) xx 300`
    ` = 0.014 cm`.

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