A box contains `15` green and `10` yellow balls. If `10` balls are randomly drawn, one-by-one, with replacement, then the variance of the number of green balls drawn is : (a) `12/5` (b) `6` (c) `4` (d) `6/25`
A. `(12)/(5)`
B. 6
C. 4
D. `(6)/(25)`
A. `(12)/(5)`
B. 6
C. 4
D. `(6)/(25)`
Correct Answer – A
Given box contains 15 green and 10 yellow balls.
`:. Total number of balls `=15+10=25`
P(green balls)=`(15)/(25)=(3)/(5)`=p=Probability of success
P(yellow balls)`=(10)/(25)=(2)/(5)=q`=Probability of unsuccess and n=10=Number of trials.
`:. “Variance” =npq=10xx(3)/(5)xx(2)/(5)=(12)/(5)`