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Komal Borah
Asked: 2022-11-09T20:25:42+05:30 In:

A body of length `1 m` having cross sectional area `0.75 m^(2)` has heat flow through it at the rate of `6000 “Joule”//sec`. Then find the temperature difference if `K = 200 Jm^(-1) K^(-1)`.
A. `20^(@)C`
B. `40^(@)C`
C. `80^(@)C`
D. `100^(@)C`

A body of length `1 m` having cross sectional area `0.75 m^(2)` has heat flow through it at the rate of `6000 “Joule”//sec`. Then find the temperature difference if `K = 200 Jm^(-1) K^(-1)`.
A. `20^(@)C`
B. `40^(@)C`
C. `80^(@)C`
D. `100^(@)C`
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  1. Correct Answer – B
    `Q=(KA(Deltathetat))/(l)`

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Aruna Rama
Asked: 2022-11-01T23:35:15+05:30 In:

A body of length `1 m` having cross sectional area `0.75 m^(2)` has heat flow through it at the rate of `6000 “Joule”//sec`. Then find the temperature difference if `K = 200 Jm^(-1) K^(-1)`.
A. `20^(@)C`
B. `40^(@)C`
C. `80^(@)C`
D. `100^(@)C`

A body of length `1 m` having cross sectional area `0.75 m^(2)` has heat flow through it at the rate of `6000 “Joule”//sec`. Then find the temperature difference if `K = 200 Jm^(-1) K^(-1)`.
A. `20^(@)C`
B. `40^(@)C`
C. `80^(@)C`
D. `100^(@)C`
Parabola
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1 Answer

  1. Correct Answer – B
    `Q/t = (KADelta theta)/(l)`
    `rArr 6000=(200xx0.75xxDelta theta)/(1)`
    `:. Delta theta = (6000xx1)/(200xx0.75) = 40^(@)C`.

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