A ball is dropped onto a horizontal surface from a height of 36 cm. After bouncing several times it comes to rest covering a total distance of 100 cm measured in a vertical direction. The percentage loss in its kinetic energy after its first impact is
(a) 36 (b) 64 (c) 53 (d) 96
Correct option (c) 53
Explanation:
One can write the series 100 = 36 + 2 x 36 (e2 + e4 + e6 + ..) giving e2 = 8/17 where e is the coefficient of restitution. Now, the percentage loss of kinetic energy = change in kinetic energy/original kinetic energy x 100. Note that the speed after impact is e times the initial speed. This gives the percentage loss as 52.94 which is almost 53 %.