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Mridula Krishna
Mridula Krishna
Asked: 3 years ago2022-11-05T09:01:20+05:30 2022-11-05T09:01:20+05:30In: Nsep

A ball is dropped onto a horizontal surface from a height of 36 cm. After bouncing several times it comes to rest covering a total distance of 100 cm measured in a vertical direction. The percentage loss in its kinetic energy after its first impact is

(a) 36 (b) 64 (c) 53 (d) 96 

A ball is dropped onto a horizontal surface from a height of 36 cm. After bouncing several times it comes to rest covering a total distance of 100 cm measured in a vertical direction. The percentage loss in its kinetic energy after its first impact is

(a) 36 (b) 64 (c) 53 (d) 96 

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  1. f0022
    2022-11-09T14:05:46+05:30Added an answer about 3 years ago

    Correct option  (c)  53

    Explanation:

    One can write the series 100 = 36 + 2 x 36 (e2 + e4 + e6 + ..) giving  e2 = 8/17 where e is the coefficient of restitution. Now, the percentage loss of kinetic energy = change in kinetic energy/original kinetic energy x 100. Note that the speed after impact is e times the initial speed. This gives the percentage loss as 52.94 which is almost 53 %.

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