A bag contains cards numbered from 1 to 25. A card is drawn at random from the bag. The probability that the number on this card is divisible by both 2 and 3 is
A. \(\frac{1}5\)
B. \(\frac{3}{25}\)
C. \(\frac{4}{25}\)
D.\(\frac{2}{25}\)
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A bag contains cards numbered from 1 to 25. A card is drawn at random from the bag. The probability that the number on this card is divisible by both 2 and 3 is
A. \(\frac{1}5\)
B. \(\frac{3}{25}\)
C. \(\frac{4}{25}\)
D.\(\frac{2}{25}\)
A bag contains cards numbered from 1 to 25. A card is drawn at random from the bag. The probability that the number on this card is divisible by both 2 and 3 is
A. \(\frac{1}5\)
B. \(\frac{3}{25}\)
C. \(\frac{4}{25}\)
D.\(\frac{2}{25}\)
Total numbers of elementary events are: 25
Let E be the event of getting number divisible by both 2 and 3
Favorable outcomes are: { 6, 12, 18, 24}
Numbers of favorable outcomes are: 4
P (number divisible by 2 and 3) = P (E) = \(\frac{4}{25}\)