A bag contains 8 white, 5 black and 4 blue balls. One ball is drawn randomly, what is the probability that it is neither white nor blue ball?
1. 5/17
2. 8/17
3. 4/17
4. 6/17
1. 5/17
2. 8/17
3. 4/17
4. 6/17
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Correct Answer – Option 1 : 5/17
Given:
Total number of balls in box = (4 blue + 5 black + 8 white) balls = 17 balls
Formula used:
Probability of event = (Number of favourable outcomes)/(Total number of outcomes)
Calculations:
Let,
E1 = event of picking a white ball
E2 = event of picking a blue ball
Then,
P(E1 ) = 8/17
P(E2) = 4/17
⇒ Probability of picking a cap that it is either blue or white = 4/17 + 8/17 = 12/17
the probability that it is neither white nor blue ball = 1 -12/17 = 5/17
∴ The probability that it isneither white nor blue ball is 5/17