A bag contains 7 blue towels, 5 green towels, and 8 red towels. Two towels are drawn randomly. What is the probability that both are green?
1. 1/38
2. 1/19
3. 1/29
4. 1/18
5. None of these
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Correct Answer – Option 2 : 1/19
Given:
Green towel = 5
Blue towel = 7
Red towel = 8
Formula:
Probability (E) = Favourable outcomes/Total possible outcomes
Note: here, Probability denoted by ‘E’
The formula used for combination is –
nCr = n!/(n – r)! × r!
Here,
n = Sample of items.
r = Items are taken at a time.
Calculation:
Favourable outcomes –
2 (out of 5)
5C2 = 5!/(5 – 2)! × 2!
⇒ 5!/3! × 2!
⇒ 5 × 4 × (3!/3!) × 2!
⇒ 5 × (4/2) × 1
⇒ 20/2
⇒ 10
∴ Favourable outcomes will be 10
Total possible outcomes –
2 (out of 20)
20C2 = 20!/(20 – 2)! × 2!
⇒ (20!/18!) × 2!
⇒ 20 × 19 × (18!/18!) × 2!
⇒ 20 × (19/2) × 1
⇒ 10 × 19
⇒ 190
∴ Total possible outcomes will be 190
Now,
Probability (E) = Favourable outcomes/Total possible outcomes
Probability (E) = 10/190
⇒ 1/19
∴ The Probability that both are green will be 1/19