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A bag contains 18 balls out of which x balls are red.
(i) If the ball is drawn at random from the bag, what is the probability that it is not red?
(ii) If two more red balls are put in the bag, the probability of drawing a red ball will be 9/8 times the probability of drawing a red ball in the first case. Find the value of x.
A bag contains 18 balls out of which x balls are red.
(i) If the ball is drawn at random from the bag, what is the probability that it is not red?
(ii) If two more red balls are put in the bag, the probability of drawing a red ball will be 9/8 times the probability of drawing a red ball in the first case. Find the value of x.
Total number of balls = 18
(i) Let x be number of red balls. So, there are (18 – x) non red balls.
P(getting a non red ball) = (18-x)/18
(ii) if 2 more red balls are out in the bag, then there are 20 total number of balls.
Number of red balls x + 2
So we have,
P(getting a red ball) = 9/8 p(getting a red ball in first option)
Now,
(x+2)/20 = 9/8(x/18)
16x + 32 = 20x
X = 8