a2-b2
(a+b)(a-b)=a2-b2(a+b)(a-b)=a(a-b)+b(a-b)=a2-ab+ab-b2 =a2-b2\xa0\xa0\xa0\xa0
(a+b)(a-b)
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(a-b)(a+b)
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a ^2 + b ^2
a2-b2
|A+B|=|A-B|
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True only when A and B both are positive integer
(a+b)(a+b)
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(a^+b^+2ab )
a²+b²+2ab
(a+b)^2
(a+b) (a-b) = ?
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a-2_b-2
a^2 – b^2
a^2 – b^2
a ka sqare -b ka square
“a” ka Square -“b” ka square
a^2-b^2
It is a formula (a+b)(a-b) = a^2-b^2Or else u can also solve the equation in a general manner . The same will be as follows(a+b)(a-b) = a*a + a*-b + a*b + b*-b=a^2-ab+ab-b^2=a^2-b^2
a ka square plus b ka square
(a+b) (a-b)=
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a^2-b^2 i.e. a square- b square
(a+b)(a-b) =
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A^2 + B^2
A^2-B^2
a(a-b)+b(a-b)a2-ab+ab-b2:.:. /(a2 – b2)/
A² – B²
a2 – b2
A +B A_B
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(A+B)+(a-b)
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(a-b)(a+b)=?
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a2-b2
a2-b2
a square – b square
(a+b)(a-b)
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Lol
(a+b)(a-b) =a²-ab+ab-b²=a²+b²
(a+b) (a-b)
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a^2 – b^2
a^2-b^2
its a^2\’b^2
a^2-b^2
(a+b)*(a-b)
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a²-b² ?
a^2-b^2
a^2-b^2
(a+b) (a_b)
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Bhai aaj hindi ka paper hai aur tu maths le kr baitha hai
a^2-b^2
(A+b)*(a+b)
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Sorry this is correct ansAa+Ab+ba+bb
Aa +Ab+Ba+Bb
Aa+Ab+ba+bb
(a+b) (a-b)
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a^2 – b^2
a²-b²
A square minus b square
a^2 -b^2
a2-b2
(A+b)( a-b)
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a2- b2
a^2-b^2
(a + b)( a – b) = a2 – b2
A square-B square
A square ×B square
(a+b)a_b
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If ques. is this then,ans- a^2+ab-b
(a-b) (a+b)
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No no sorry a^2- b^2
(a-b)^2
(a-b)2
a^2-b^2
(a² – b²)
(a+b) (a-b)= ?
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Its an identity which is (a+b)(a-b)=a^2-b^2
A^2 – B^2
[a+b] [a+b]
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(a+b)^2=a^2-b^2+2ab
(a+b)² =a²+ b²+ 2ab
a²+b²+2ab
a²+b²
a²+b²
(a+b)( a-b )
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(a+b)(a-b)=a square – b square where a and b are the two terms
=(a+b)(a-b)=a^2-b^2
(a+b) (a+b)
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(a+b)whole square
a+b a-b=
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(A+B)(A+B)
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(A+B) (A+B) = A² + B² +2AB
A square +b square + 2ab
a2-b2