3x +5y =2 2x – y = 3 , solve this by substitution method
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Y =34-39/13-5/13
3x +5y= 2 ~equation 12x-y=3. Or 2x-3=y ~equ 2By putting the value of y in equation 2 we get3x+5×(2x-3)=23x+10x-15=213x=2+15X=17/13Then putting he value of x in equation 2 we get the value of y2(17/13)-3=yY=(34/13)-334-39/3Y=-5/3
Let, 3x+5y=2. is eq1 2x – y =3. is eq2In eq1, 3x + 5y =2 5y=2-3x y= 2 /5- 3x/5From eq1 we get, y= 2/5 – 3x/5 Now, We substitute y\’s value in eq2 2x – (2/5-3x/5)=3 2x -2/5+3x/5=3 10x-2+3x/5=3 13x-2=15 13X =15+2 X. =17/13Now, we find x=17/13 In eq1 we put x=17/13 3(17/13)+5y=2 51/13+5y=2 5y= 2-51/13 5y=26-51/13 5y=-25/13 Y= -25/13 ×5 Y=-5/13 Hence,we find x=17/13 and y= -5/13.