20 ” mL of ” `(M)/(60)` `KBrO_3` was reacted with a sample of `SeO_(3)^(2-)` 20 The `Br_(2)` thus evolved was removed and the excess of `NaAsO_(2)` The reaction involved are
`SeO_(3)^(2-)+BrO_(3)^(ɵ)+H^(o+)toSeO_(4)^(2-)+Br_(2)+H_(2)O` .. (i)
`BrO_(3)^(ɵ)+ASO_(2)^(ɵ)+H_(2)OtoBr^(ɵ)+AsO_(4)^(3-)+H^(o+)` ..(ii)
`[Mw(SeO_(3)^(2-))=79+48=127gmol^(-1)]`
Q. m” Eq of “`SeO_(3)^(2-)` is
A. `(55)/(72)`
B. `(55)/(36)`
C. `(11)/(36)`
D. `(11)/(6)`
`SeO_(3)^(2-)+BrO_(3)^(ɵ)+H^(o+)toSeO_(4)^(2-)+Br_(2)+H_(2)O` .. (i)
`BrO_(3)^(ɵ)+ASO_(2)^(ɵ)+H_(2)OtoBr^(ɵ)+AsO_(4)^(3-)+H^(o+)` ..(ii)
`[Mw(SeO_(3)^(2-))=79+48=127gmol^(-1)]`
Q. m” Eq of “`SeO_(3)^(2-)` is
A. `(55)/(72)`
B. `(55)/(36)`
C. `(11)/(36)`
D. `(11)/(6)`
Correct Answer – B
m” mol of “`BrO_(3)^(ɵ)` reacted with `SeO_(3)^(2-)` in equation (i)
`=(11)/(36) m” mol of “BrO_(3)^(ɵ)`
`=(11)/(36)xx5` (n-factor `BrO_(3)^(ɵ)` in equation (i))
`=(55)/(36)m” Eq of “BrO_(3)^(ɵ)-=m” Eq of “SeO_(3)^(2-)` reacrted