20 mL of HCI soution requires 19.85 mL of 0.01 M NaOH solution for complete neutralization . The molarity of HCI solution is _______M.
A. `0.0099`
B. `0.0099`
C. `0.99`
D. `0.1M`
A. `0.0099`
B. `0.0099`
C. `0.99`
D. `0.1M`
Correct Answer – A
`M_(1)V_(1)=M_(2)V_(2)`
`20xxM_(HCI)=19.85xx0.01`
`M_(HCI)=(19.85xx0.01)/(20)=0.0099`