10 moles of an ideal gas expand isothermally and reversibly from a pressure of5 atm to 1 atm at300 K . What is the largest mass that can be lefted through a height of 1 metre by this expansion?
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`w_(exp) = – 2.303 nRT log.(P_(1))/(P_(2))= -2.303 ( 10 mol) xx( 8.314 JK^(-1) mol^(-1)) ( 300 K ) log. ( 5)/(1) = – 40.15 xx 10^(3)J`
If M is the mass that can be lifted by this work ,through a height of 1metre, then work done `=` Mgh
` 40.15xx 10^(3)J= Mxx9.81 m s^(-2) xx 1m`
or ` M =( 40.15 xx10^(3) kg m^(2) s^(-2))/( 9.18 ms^(-2)xx 1 m ) (J = kg m^(2) s^(-2))`
`= 4092 .76 kg`