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Akshay Inani
Asked: 2022-11-10T15:51:35+05:30 In:

`1` litre solution of unknown molarity is titrated by taking its `50 mL` solution against `KI` solution is strong acidic medium of excess `HCl`. The equivalence point was detected when `10 mL` of `0.1 M KI` was consumed The molarity of `KIO_(3)` solution is:
A. `4xx10^(-4)M`
B. `2xx10^(-2)M`
C. `4xx10^(-3)M`
D. `2xx10^(-3)M`

`1` litre solution of unknown molarity is titrated by taking its `50 mL` solution against `KI` solution is strong acidic medium of excess `HCl`. The equivalence point was detected when `10 mL` of `0.1 M KI` was consumed The molarity of `KIO_(3)` solution is:
A. `4xx10^(-4)M`
B. `2xx10^(-2)M`
C. `4xx10^(-3)M`
D. `2xx10^(-3)M`
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  1. Correct Answer – C
    Meq.of `KIO_(3)=”Meq.of” KI`
    `{:(2I^(5+)+,10e,rarr,I_(2)^(0),),(,2I^(-),rarr,I_(2)^(0)+,2e):}`
    `Mxx5xx50=10xx0.1xx1 rArrM=4.0xx10^(-3)`

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