`1 Lit`. Of aq. Solution of urea having density`=1.060gm//mL` is found to have `DeltaT_(b)=0.5^(@)C`, if temp. of this solution increase to `101.5^(@)C` then calculate amount of water which must have gone is vapour state upto this pt. given `K_(b)=0.5K kg mol^(-1)` for water
`0.5=0.5xx(1060)/(1060)(M)/(60) rArr 1060xx60=M`
`1` Lit solution`=1060gm`
(Mass of water)`|=1000gm`
urea`=60gm`
`DeltaT_(b)=(“molality”)=K_(b)`
(Molality) `rArr 3=(60)/(60)xx(1000)/(W_(“water”)`
`W_(“water”)=(1000)/(3)gm`.
mass of water vaporised`=1000-(2000)/(3)gm=666.67gm`