1/5th of cistern can be emptied in 2 hours. Calculate what percentage of tank was filled if it takes 6 hours to empty that amount of tank
1. 25%
2. 60%
3. 50%
4. 40%
5. 45%
1. 25%
2. 60%
3. 50%
4. 40%
5. 45%
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Correct Answer – Option 2 : 60%
Given:
1/5th of cistern emptied = 2 hours
Calculation:
1/5th of cistern is emptied in 2 hours
⇒ Time taken to empty the whole cistern = 2 × (5/1)
⇒ Time taken to empty the whole cistern = 10 hours
Now, Within 6 hours cistern was emptied
⇒ 10 hours to empty whole cistern = T1
⇒ 6 hours to empty particular portion of cistern = T2
⇒ Proportion of cistern = T2/T1
⇒ Proportion of cistern = 6/10
⇒ Proportion of cistern = 3/5
⇒ Percentage of cistern filled = 3/5 × 100
∴ Cistern was filled up to 60% of capacity