1*2^2+2*3^2+3*4^2……….to n term
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I know it is lengthy but ….if u will read it step by step u will find it….easy
And after finding nth term multiply nth terms of both of them…then u will get….n(n^2) which will give u n^3 and then…taking summation ….as sigma n^3 apply formula and u will get answer
As given in question…..1×2^2 + 2×3^2…firstly separate the no.s in multiplication ….u can write….(1+2+3……..)(2^2 + 3^2 + 4^2………)then find nth term of each…u will get nth term of (1+2+3…..)=n and nth term of other one will be….n^2