ABC is a triangle in which altitudes BD and CE to sides AC and AB are equal (see figure). Show that 

i) ΔABD ≅ ΔACE 

ii) AB = AC i.e., ABC is an isosceles triangle.

One angle of a right angled triangle is 70°. Find the other acute angle.

AB is a line segment and P is its mid-point. D and E are points on the same side of AB such that ∠BAD = ∠ABE and ∠EPA = ∠DPB (See the given figure). Show that 

(i) ΔDAP ≅ ΔEBP

(ii) AD = BE