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    Kajal Amrit Kant
    Kajal Amrit Kant
    Asked: 3 years agoIn:

    Entropy is a state function and its value depends on two or three variable temperature (T), Pressure(P) and volume (V). Entropy change for an ideal gas having number of moles(n) can be determined by the following equation.
    `DeltaS=2.303 “nC”_(v)”log”((T_(2))/(T_(1))) + 2.303 “nR log” ((V_(2))/(V_(1)))`
    `DeltaS=2.303 “nC”_(P) “log”((T_(2))/(T_(1))) + 2.303 “nR log” ((P_(1))/(P_(2)))`
    Since free energy change for a process or a chemical equation is a deciding factor of spontaneity , which can be obtained by using entropy change `(DeltaS)` according to the expression, `DeltaG = DeltaH -TDeltaS` at a temperature `T`
    An isobaric process having one mole of ideal gas has entropy change `23.03` J/K for the temperature range `27^(@)` C to `327^(@)` C . What would be the molar specific heat capacity `(C_(v))`?
    A. `(10)/(“log”2) J//K mol`
    B. `(10)/(“log”2) – 8.3 J//K` mol
    C. `10 xx “log”2 J//K mol`
    D. `10 log2 + 8.3 J//k` mol

    Parabola
    Kajal Amrit Kant
    Kajal Amrit Kant
    Asked: 3 years agoIn:

    Parabola
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