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Shashank Goda

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  • mcqoptions.com Latest Questions

    Shashank Goda
    Shashank Goda
    Asked: 3 years agoIn: Class 10

    Trigonomatery

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    Shashank Goda
    Shashank Goda
    Asked: 3 years agoIn: Class 10

    CBSE new sample paper for Hindi class 10

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    Shashank Goda
    Shashank Goda
    Asked: 3 years agoIn: Class 11

    What is different between simple leaves and compound leave

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    Shashank Goda
    Shashank Goda
    Asked: 3 years agoIn: General Awareness

    According to the villagers, what was Roof’s motivation for leaving a promising career?

    Parabola
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    Shashank Goda
    Shashank Goda
    Asked: 3 years agoIn: Class 11

    histology

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    Shashank Goda
    Shashank Goda
    Asked: 3 years agoIn: General Awareness

    The potential energy of configuration changes in x and y directions as `U=kxy`, where k is a positive constant. Find the force acting on the particle of the system as the function of x and y.

    Parabola
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    Shashank Goda
    Shashank Goda
    Asked: 3 years agoIn: Class 10

    Does valli have friends? if yes give reason if No give reason.

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    Shashank Goda
    Shashank Goda
    Asked: 3 years agoIn: Class 11

    Write conjugate base of hcl

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    Shashank Goda
    Shashank Goda
    Asked: 3 years agoIn: Class 10

    Write a balanced chemical equation.Zinc + Silver nitrate ——> Zinc nitrate + Silver

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    Shashank Goda
    Shashank Goda
    Asked: 3 years agoIn: General Awareness

    Liquid water freezes at 273K under external pressure of 1atm . The process is at eruilibrium
    `H_(2)O(l)toH_(2)O(S)at 273 Kand 1atm`
    however , it required to calculate the thermodynamic parameters of the fusion process occurring at same pressure and different temperature . Using the following dat ,answer the questions thaat follow:
    `d_(ice)=0.9gm //cc,d_(H_(2)O(l))=1gm //c”c”,1L-atm =101.3 J `
    `C_(p)[H_(2)O(s)]=36.4JK^(-1)mol^(-1)`
    `C_(p)[H_(2)O(l)]=75.3Jk^(-1)mol^(-1)`
    `DeltaH_(“fusion”)=6008.2mol^(-1).Alldataat 273K.`
    the value of `DeltaH_(“fusion”)` at 263 K and 1 atm will be :
    A. `+6008.0K”mole”^(-1)`
    B. `5619.2J “mole”^(-1)`
    C. `-5619.2J “mole”^(-1)`
    D. `6619.2 “mole”^(-1)`

    Parabola
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