\[(z+a)(\bar{z}+a)\], where \[a\] is real, is equivalent to

1.	\[(z+a)(\bar{z}+a)\], where \[a\] is real, is equivalent to
A.	\[\|z-a\|\]
B.	\[{{z}^{2}}+{{a}^{2}}\]
C.	\[\|z+a{{\|}^{2}}\]
D.	None of these
Answer» D. None of these

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\[(z+a)(\bar{z}+a)\], where \[a\] is real, is equivalent to

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