\[|{{z}_{1}}+{{z}_{2}}|\,=\,|{{z}_{1}}|+|{{z}_{2}}|\] is possible if [MP PET 1999; Pb. CET 2002]

\[{{z}_{2}}={{\overline{z}}_{1}}\]

\[{{z}_{2}}=\frac{1}{{{z}_{1}}}\]

\[arg\,({{z}_{1}})=\]arg \[({{z}_{2}})\]

\[|{{z}_{1}}+{{z}_{2}}|\,=\,|{{z}_{1}}|+|{{z}_{2}}|\] is possible if [

1.	\[\|{{z}_{1}}+{{z}_{2}}\|\,=\,\|{{z}_{1}}\|+\|{{z}_{2}}\|\] is possible if [MP PET 1999; Pb. CET 2002]
A.	\[{{z}_{2}}={{\overline{z}}_{1}}\]
B.	\[{{z}_{2}}=\frac{1}{{{z}_{1}}}\]
C.	\[arg\,({{z}_{1}})=\]arg \[({{z}_{2}})\]
D.	\[\|{{z}_{1}}\|\,=\,\|{{z}_{2}}\|\]
Answer» D. \[\|{{z}_{1}}\|\,=\,\|{{z}_{2}}\|\]

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\[|{{z}_{1}}+{{z}_{2}}|\,=\,|{{z}_{1}}|+|{{z}_{2}}|\] is possible if [MP PET 1999; Pb. CET 2002]

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