\[y+{{x}^{2}}=\frac{dy}{dx}\] has the solution [EAMCET 2002]

\[y+x+{{x}^{2}}+2=c{{e}^{2x}}\]

\[y+{{x}^{2}}+2x+2=c{{e}^{x}}\]

\[y+x+2{{x}^{2}}+2=c{{e}^{x}}\]

\[{{y}^{2}}+x+{{x}^{2}}+2=c{{e}^{x}}\]

\[y+{{x}^{2}}=\frac{dy}{dx}\] has the solution [EAMC

1.	\[y+{{x}^{2}}=\frac{dy}{dx}\] has the solution [EAMCET 2002]
A.	\[y+{{x}^{2}}+2x+2=c{{e}^{x}}\]
B.	\[y+x+{{x}^{2}}+2=c{{e}^{2x}}\]
C.	\[y+x+2{{x}^{2}}+2=c{{e}^{x}}\]
D.	\[{{y}^{2}}+x+{{x}^{2}}+2=c{{e}^{x}}\]
Answer» B. \[y+x+{{x}^{2}}+2=c{{e}^{2x}}\]

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\[y+{{x}^{2}}=\frac{dy}{dx}\] has the solution [EAMCET 2002]

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