

MCQOPTIONS
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1. |
x3 Sin(y) + Cos(x) y3 = 0, its differentiation is? |
A. | \(-\frac{[x^3 Sin(y)-3y^2 Sin(x)]}{[x^2 Cos(y)+y^3 Cos(x)]}\) |
B. | \(-\frac{[3x^2 Sin(y)-y^3 Sin(x)]}{[x^3 Cos(y)+3y^2 Cos(x)]}\) |
C. | \(-\frac{[3x^3 Sin(y)-y^3 Sin(x)]}{[x^3 Cos(y)+3y^3 Cos(x)]}\) |
D. | 0 |
Answer» C. \(-\frac{[3x^3 Sin(y)-y^3 Sin(x)]}{[x^3 Cos(y)+3y^3 Cos(x)]}\) | |