1.

With variable thermal conductivity, Fourier law of heat conduction through a plane wall can be expressed as

A. Q = -k0 (1 + β t) A d t/d x
B. Q = k0 (1 + β t) A d t/d x
C. Q = – (1 + β t) A d t/d x
D. Q = (1 + β t) A d t/d x
Answer» B. Q = k0 (1 + β t) A d t/d x


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