Why only \[A{{s}^{3+}}\] gets precipitated as \[A{{s}_{2}}{{S}_{3}}\] and not \[Z{{n}^{2+}}\]as ZnS when \[{{H}_{2}}S\] is passed through an acidic solution containing \[A{{s}^{3+}}\] and\[Z{{n}^{2+}}\]?

Enough \[A{{s}^{3+}}\]are present in acidic medium

Solubility product of \[A{{s}_{2}}{{S}_{3}}\] is less than that of ZnS

Zinc salt does not ionise in acidic medium

Solubility product changes in presence of an acid

Why only \[A{{s}^{3+}}\] gets precipitated as \[A{{s}_{2}}{{S}_{3}}\]

1.	Why only \[A{{s}^{3+}}\] gets precipitated as \[A{{s}_{2}}{{S}_{3}}\] and not \[Z{{n}^{2+}}\]as ZnS when \[{{H}_{2}}S\] is passed through an acidic solution containing \[A{{s}^{3+}}\] and\[Z{{n}^{2+}}\]?
A.	Solubility product of \[A{{s}_{2}}{{S}_{3}}\] is less than that of ZnS
B.	Enough \[A{{s}^{3+}}\]are present in acidic medium
C.	Zinc salt does not ionise in acidic medium
D.	Solubility product changes in presence of an acid
Answer» B. Enough \[A{{s}^{3+}}\]are present in acidic medium

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Why only \[A{{s}^{3+}}\] gets precipitated as \[A{{s}_{2}}{{S}_{3}}\] and not \[Z{{n}^{2+}}\]as ZnS when \[{{H}_{2}}S\] is passed through an acidic solution containing \[A{{s}^{3+}}\] and\[Z{{n}^{2+}}\]?

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