1.

When the object is self-luminous, the resolving power of a microscope is given by the expression

A. \[\frac{2\mu \sin \theta }{1.22\,\lambda }\]
B. \[\frac{\mu \sin \theta }{\lambda }\]
C. \[\frac{2\mu \cos \theta }{1.22\ \lambda }\]
D. \[\frac{2\mu }{\lambda }\]
Answer» B. \[\frac{\mu \sin \theta }{\lambda }\]


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