When simplified, \[{{\text{(}{{\text{x}}^{-1}}+{{y}^{-1}})}^{-1}}\] is equal to_____.

When simplified, \[{{\text{(}{{\text{x}}^{-1}}+{{y}^{-1}})}^{-1}}\] is

1.	When simplified, \[{{\text{(}{{\text{x}}^{-1}}+{{y}^{-1}})}^{-1}}\] is equal to_____.
A.	\[x+y\]
B.	\[\frac{xy}{x+y}\]
C.	\[xy\]
D.	\[\frac{1}{xy}\]
Answer» C. \[xy\]

Discussion

No Comment Found

Related MCQs

The value of \[\frac{\mathbf{10}{{\mathbf{0}}^{\mathbf{98}}}\mathbf{+10}{{\mathbf{0}}^{\mathbf{100}}}}{\mathbf{10}{{\mathbf{0}}^{\mathbf{98}}}}\]+1 is equal to________.
If \[\mathbf{m = }{{\mathbf{7}}^{\mathbf{-}}}^{\mathbf{7}}\mathbf{- }{{\mathbf{7}}^{\mathbf{7}}}\mathbf{and n = }{{\mathbf{7}}^{\mathbf{7}}}\mathbf{- }{{\mathbf{7}}^{\mathbf{-}}}^{\mathbf{7}}\], then find the value of \[\frac{\mathbf{m}}{\mathbf{n}}\mathbf{-}\frac{\mathbf{n}}{\mathbf{m}}\].
Find the unit's digit in the product of \[\frac{{{2}^{32}}\times {{3}^{42}}\times {{847}^{42}}}{{{9}^{14}}}\].
Simplify \[{{\left( \frac{{{a}^{-2}}}{{{b}^{-2}}} \right)}^{-3}}\left( \frac{{{a}^{-3}}}{{{b}^{-5}}} \right)\]
Evaluate \[{{\left[ {{\left( \sqrt{\frac{2}{3}} \right)}^{2}}-\sqrt[3]{\frac{8}{27}} \right]}^{1000}}\]
If \[x={{\left( \frac{3}{2} \right)}^{2}}\times {{\left( \frac{2}{3} \right)}^{-4}}\], find the value of \[{{x}^{2}}\].
Evaluate \[{{\left\{ {{\left( \frac{3}{4} \right)}^{-1}}-{{\left( \frac{1}{4} \right)}^{-1}} \right\}}^{-1}}\].
Simplify \[\frac{{{(16{{a}^{2}})}^{\frac{1}{2}}}\times {{(36\,{{a}^{4}})}^{\frac{-1}{2}}}}{2{{a}^{\frac{1}{2}}}\times 5{{a}^{\frac{3}{2}}}\times 8{{a}^{\frac{9}{4}}}}\].
Mr Gupta asked two of his students to solve the expression \[{{\left( \frac{9{{a}^{3}}{{b}^{-8}}}{81{{a}^{-5}}{{b}^{2}}} \right)}^{-\frac{1}{2}}}\]and write the answer on blackboard. Aryan wrote the answer as \[3{{a}^{-4}}{{b}^{5}}\] whereas Ayan wrote the answer as \[\frac{3{{b}^{5}}}{{{a}^{4}}}\].Who wrote the correct answer?
Find the value of \[{{16}^{\frac{3}{4}}}\times {{4}^{\frac{-1}{2}}}.\]

When simplified, \[{{\text{(}{{\text{x}}^{-1}}+{{y}^{-1}})}^{-1}}\] is equal to_____.

Discussion

No Comment Found

Related MCQs

Reply to Comment