1.

When Al is added to \[NaOH\] solution

A. No action takes place
B. \[NaAl{{O}_{2}}\] is formed and \[{{H}_{2}}\] is evolved
C. \[Al{{\left( OH \right)}_{3}}\] is formed and \[{{H}_{2}}\] is evolved
D. \[N{{a}_{2}}Al{{O}_{2}}\] is formed and\[{{H}_{2}}\]is evolved
Answer» C. \[Al{{\left( OH \right)}_{3}}\] is formed and \[{{H}_{2}}\] is evolved


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