MCQOPTIONS
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| 1. |
When a beam of 10.6 eV photons of intensity \[2.0\text{ }W/{{m}^{2}}\,\] falls on a platinum surface of area \[1.0\times {{10}^{-4}}{{m}^{2}}\] and work function 5.6 eV, 0.53% of the incident photons eject photoelectrons, then the number of photoelectrons emitted per second and their minimum & maximum energies (in eV) [Take \[1eV=1.6\times {{10}^{-19}}J\]] are respectively. |
| A. | \[1.18\times {{10}^{10}},2eV,5eV\] |
| B. | \[1.18\times {{10}^{14}},0eV,5eV\] |
| C. | \[2.18\times {{10}^{13}},0eV,5eV\] |
| D. | \[3.11\times {{10}^{11}},1eV,5eV\] |
| Answer» C. \[2.18\times {{10}^{13}},0eV,5eV\] | |