What will be the output of the program?
#include
int main()
{
unsigned int i = 65536; /* Assume 2 byte integer*/
while(i != 0)
printf("%d",++i);
printf("
");
return 0;
}

Question

What will be the output of the program?
#include
int main()
{
    unsigned int i = 65536; /* Assume 2 byte integer*/
    while(i != 0)
        printf("%d",++i);
    printf("
");
    return 0;
}

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

Infinite loop

TuteeHUB · Answer

0 1 2 ... 65535

TuteeHUB · Answer

0 1 2 ... 32767 - 32766 -32765 -1 0

TuteeHUB · Answer

No output

1.	What will be the output of the program? #include int main() { unsigned int i = 65536; /* Assume 2 byte integer*/ while(i != 0) printf("%d",++i); printf("\n"); return 0; }
A.	Infinite loop
B.	0 1 2 ... 65535
C.	0 1 2 ... 32767 - 32766 -32765 -1 0
D.	No output
Answer» E.

What will be the output of the program? #include int main() { unsigned int i = 65536; /* Assume 2 byte integer*/ while(i != 0) printf("%d",++i); printf("\n"); return 0; }

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