What will be the output of the program?
public class RTExcept
{
public static void throwit ()
{
System.out.print("throwit ");
throw new RuntimeException();
}
public static void main(String [] args)
{
try
{
System.out.print("hello ");
throwit();
}
catch (Exception re )
{
System.out.print("caught ");
}
finally
{
System.out.print("finally ");
}
System.out.println("after ");
}
}

Question

What will be the output of the program?
public class RTExcept 
{
    public static void throwit () 
    {
        System.out.print("throwit ");
        throw new RuntimeException();
    }
    public static void main(String [] args) 
    {
        try 
        {
            System.out.print("hello ");
            throwit();
        }
        catch (Exception re ) 
        {
            System.out.print("caught ");
        }
        finally 
        {
            System.out.print("finally ");
        }
        System.out.println("after ");
    }
}

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

hello throwit caught

TuteeHUB · Answer

Compilation fails

TuteeHUB · Answer

hello throwit RuntimeException caught after

TuteeHUB · Answer

hello throwit caught finally after

1.	What will be the output of the program? public class RTExcept { public static void throwit () { System.out.print("throwit "); throw new RuntimeException(); } public static void main(String [] args) { try { System.out.print("hello "); throwit(); } catch (Exception re ) { System.out.print("caught "); } finally { System.out.print("finally "); } System.out.println("after "); } }
A.	hello throwit caught
B.	Compilation fails
C.	hello throwit RuntimeException caught after
D.	hello throwit caught finally after
Answer» E.

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