What will be the output of the program?
class Exc0 extends Exception { }
class Exc1 extends Exc0 { } /* Line 2 */
public class Test
{
public static void main(String args[])
{
try
{
throw new Exc1(); /* Line 9 */
}
catch (Exc0 e0) /* Line 11 */
{
System.out.println("Ex0 caught");
}
catch (Exception e)
{
System.out.println("exception caught");
}
}
}

Question

What will be the output of the program?
class Exc0 extends Exception { } 
class Exc1 extends Exc0 { } /* Line 2 */
public class Test 
{  
    public static void main(String args[]) 
    { 
        try 
        {  
            throw new Exc1(); /* Line 9 */
        } 
        catch (Exc0 e0) /* Line 11 */
        {
            System.out.println("Ex0 caught"); 
        } 
        catch (Exception e) 
        {
            System.out.println("exception caught");  
        } 
    } 
}

TuteeHUB · Accepted Answer

exception caught

TuteeHUB · Answer

Ex0 caught

TuteeHUB · Answer

Compilation fails because of an error at line 2.

TuteeHUB · Answer

Compilation fails because of an error at line 9.

1.	What will be the output of the program? class Exc0 extends Exception { } class Exc1 extends Exc0 { } /* Line 2 / public class Test { public static void main(String args[]) { try { throw new Exc1(); / Line 9 / } catch (Exc0 e0) / Line 11 */ { System.out.println("Ex0 caught"); } catch (Exception e) { System.out.println("exception caught"); } } }
A.	Ex0 caught
B.	exception caught
C.	Compilation fails because of an error at line 2.
D.	Compilation fails because of an error at line 9.
Answer» B. exception caught

Discussion

No Comment Found

Related MCQs

Reply to Comment