What will be the output of the following C code?
#include <stdio.h>
void main()
{
int i = 51;
int *ptr1 = &i;
int **ptr2 = &ptr1;
printf("%d %d %d n", i, *ptr1, **ptr2);
}

Question

What will be the output of the following C code?#include <stdio.h> void main() { int i = 51; int *ptr1 = &i; int **ptr2 = &ptr1; printf("%d %d %d n", i, *ptr1, **ptr2); }

TuteeHUB · Accepted Answer

Compilation Error

TuteeHUB · Answer

51, 51, Garbage value

TuteeHUB · Answer

Garbage value, Garbage value, Garbage value

TuteeHUB · Answer

51, 51, 51

TuteeHUB · Answer

None of these

1.	What will be the output of the following C code? #include <stdio.h> void main() { int i = 51; int ptr1 = &i; int ptr2 = &ptr1; printf("%d %d %d n", i, ptr1, **ptr2); }
A.	51, 51, Garbage value
B.	Garbage value, Garbage value, Garbage value
C.	51, 51, 51
D.	Compilation Error
E.	None of these
Answer» D. Compilation Error

What will be the output of the following C code?
#include <stdio.h>
void main()
{
int i = 51;
int *ptr1 = &i;
int **ptr2 = &ptr1;
printf("%d %d %d n", i, *ptr1, **ptr2);
}

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