What will be the output of the following C code?#include <stdio.h> int n; int main() { extern int n; if (p == 0) printf("Scope rules follow here n"); }

Nothing will be printed as value of n is not zero because i is an automatic variable

Compile time error due to multiple declaration

Compile time error due to not defining type in statement extern n

What will be the output of the following C code?#include <stdio.h> int

1.	What will be the output of the following C code? #include <stdio.h> int n; int main() { extern int n; if (p == 0) printf("Scope rules follow here n"); }
A.	Scope rules followed
B.	Nothing will be printed as value of n is not zero because i is an automatic variable
C.	Compile time error due to multiple declaration
D.	Compile time error due to not defining type in statement extern n
E.	None of these
Answer» B. Nothing will be printed as value of n is not zero because i is an automatic variable

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What will be the output of the following C code?#include <stdio.h> int n; int main() { extern int n; if (p == 0) printf("Scope rules follow here n"); }

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What will be the output of the following C code?
#include <stdio.h>
int n;
int main()
{
extern int n;
if (p == 0)
printf("Scope rules follow here n");
}