What will be the output of the following C code?
#include <stdio.h>
int fun();
int main()
{
int ptr = fun();
printf("%d n", ptr);
}
int fun()
{
int p = (int)malloc(sizeof(int));
*p = 11;
return p;
}

Question

What will be the output of the following C code?

#include <stdio.h>
 int *fun();
 int main()
 {
 int *ptr = fun();
 printf("%d n", *ptr);
 }
 int *fun()
 {
 int *p = (int*)malloc(sizeof(int));
 *p = 11;
 return p;
 }

TuteeHUB · Accepted Answer

Undefined behaviour

TuteeHUB · Answer

Compilation Error

TuteeHUB · Answer

11

TuteeHUB · Answer

Undefined behaviour

TuteeHUB · Answer

Segmentation fault/runtime crash since pointer to local variable is returned

TuteeHUB · Answer

None of these

1.	What will be the output of the following C code? #include <stdio.h> int fun(); int main() { int ptr = fun(); printf("%d n", ptr); } int fun() { int p = (int)malloc(sizeof(int)); *p = 11; return p; }
A.	Compilation Error
B.	11
C.	Undefined behaviour
D.	Segmentation fault/runtime crash since pointer to local variable is returned
E.	None of these
Answer» C. Undefined behaviour

What will be the output of the following C code?
#include <stdio.h>
int fun();
int main()
{
int ptr = fun();
printf("%d n", ptr);
}
int fun()
{
int p = (int)malloc(sizeof(int));
*p = 11;
return p;
}

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What will be the output of the following C code?#include <stdio.h> int *fun(); int main() { int *ptr = fun(); printf("%d n", *ptr); } int *fun() { int *p = (int*)malloc(sizeof(int)); *p = 11; return p; }

Discussion

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What will be the output of the following C code?
#include <stdio.h>
int fun();
int main()
{
int ptr = fun();
printf("%d n", ptr);
}
int fun()
{
int p = (int)malloc(sizeof(int));
*p = 11;
return p;
}