What will be the output of the following C code? #include int *(*(x()))[2]; typedef int **(*ptrfoo)())[2]; int main() { ptrfoo ptr1; ptr1 = x; ptr1(); return 0; } int *(*(x()))[2] { int (*ary)[2] = malloc(sizeof * ary); return &ary; }

What will be the output of the following C code? #include int *(*(x(

1.	What will be the output of the following C code? #include int ((x()))[2]; typedef int *(ptrfoo)())[2]; int main() { ptrfoo ptr1; ptr1 = x; ptr1(); return 0; } int ((x()))[2] { int (ary)[2] = malloc(sizeof ary); return &ary; }
A.	Compile time error
B.	Nothing
C.	Undefined behaviour
D.	D.
Answer» C. Undefined behaviour

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What will be the output of the following C code? #include int ((x()))[2]; typedef int **(ptrfoo)())[2]; int main() { ptrfoo ptr1; ptr1 = x; ptr1(); return 0; } int (*(x()))[2] { int (ary)[2] = malloc(sizeof ary); return &ary; }

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What will be the output of the following C code? #include int *(*(x()))[2]; typedef int **(*ptrfoo)())[2]; int main() { ptrfoo ptr1; ptr1 = x; ptr1(); return 0; } int *(*(x()))[2] { int (*ary)[2] = malloc(sizeof * ary); return &amp;ary; }

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What will be the output of the following C code? #include int ((x()))[2]; typedef int **(ptrfoo)())[2]; int main() { ptrfoo ptr1; ptr1 = x; ptr1(); return 0; } int (*(x()))[2] { int (ary)[2] = malloc(sizeof ary); return &ary; }