What will be the final values of k and L in the following C code?#include <stdio.h> int n = 0; int main() { int k = (fun1() + fun2()) | fun2(); //bitwise or int L = fun2() | (fun1() + fun2()); //bitwise or } int fun1() { if (n == 0) return n + 1; else return n - 1; } int fun2() { return n++; }

What will be the final values of k and L in the following C code?#incl

1.	What will be the final values of k and L in the following C code? #include <stdio.h> int n = 0; int main() { int k = (fun1() + fun2()) \| fun2(); //bitwise or int L = fun2() \| (fun1() + fun2()); //bitwise or } int fun1() { if (n == 0) return n + 1; else return n - 1; } int fun2() { return n++; }
A.	k value is 0 and L value is 0
B.	Compilation Error
C.	k value is 1 and L value is 1
D.	Runtime Error
E.	None of these
Answer» B. Compilation Error

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What will be the final values of k and L in the following C code?
#include <stdio.h>
int n = 0;
int main()
{
int k = (fun1() + fun2()) | fun2(); //bitwise or
int L = fun2() | (fun1() + fun2()); //bitwise or
}
int fun1()
{
if (n == 0)
return n + 1;
else
return n - 1;
}
int fun2()
{
return n++;
}

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